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php json解析多层嵌套

就$data['data'][0]['province']这样呗。

php解析多层 json嵌套 for ($i = 0; $i < $count_json2; $i++) { $title = $de_json2[0]['result']['data'][0]['title']; $imtro = $de_json2[0]['result']['data'][0]['imtro']; $stepsimg1 = $de_json2[0]['result']['data'][0]['steps'][0]['...

JSONObject Gson Xstream等等的类库都可以解析 请把你的json代码提交上来

$jsonStr = '{"msg":{"auth":"Yes_auth","ddid":"1","payje":0.3,"payzt":"SUCCESS"}}';$arr = json_decode($jsonStr, true);$payzt = $arr['msg']['payzt'];// 或者$jsonStr = '{"msg":{"auth":"Yes_auth","ddid":"1","payje":0.3,"payzt":"SUC...

$json=json_decode($data,true);

$yingxiongList = array();$yingxiong = mysql_query("select * from users");while($row = mysql_fetch_array($yingxiong)){ $wuxieArr = array(); $userid = $row['Id']; $wuxie = mysql_query("select * from wuxue where userid='$userid'")...

首先,把PHP数组中的数据写入JSON文件。 然后,把JSON文件中的数据读取到PHP变量中。

$json=json_decode($data,true);

$jsonStr = '[{"text":"感觉Onedrive图片加载的速度特别慢","created":"Sat Nov 07 20:47:13 +0000 2015","favorite_count":0,"retweet_count":0,"url":"","media_url":""}]';$arr = json_decode($jsonStr, true);$text = $arr['text'];$created...

给你个思路,你结合具体项目改进吧,如下:

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